Mass and Compound Inequality Essay

To make it an equivalent inequality I replaced the IBM with the formula 702 My height in inches replaced H2O then multiply by the height that was squared 4900 canceling is performed 3300 703 1 53. 4 multiplication carried out to get W by itself all terms were divided by 703 Eater completing the problem I determined that people who are 70 inches may nave a longer that average life if they weigh between 118. 49 and 153. 34 To solve this interval I’m going to solve for W prior to solving the inequality. Multiply by H2O Divide by 703 to get W by itself it is now an equivalent inequality 703 703 703 703 from solving the first interval I know that my squared height is 4900. I then plugged it in the place of H2O then multiplied 160. 31 Divide A person of 70 inches who weighs between 160. And 172 is probably not overweight. The third interval indicates a range for a person that is probably overweight. I solved this problem by inputting the number into the last compound inequality for 23 ; 25. Multiply A person that is 70 inches tall probably is overweight if their weight is between 174. 25 and 208. 41. Interval is to be sol tort someone who is obese. IBM>30 Since this is not a compound inequality The inequality I only need to use the middle and right terms. W>147000 W>209. 10 This interval indicates a person of 70 inches in height is obese if their weight is greater than or equal to 209. 10.

Of the 4 regions I’m going to notate interval 4 which states a person is obese if their weight is greater than or equal to 209. 10. X is going to represent those who are obese (209. 10, m) Graphed it would start at 209. 10 pounds and so to infinity or it would never end. 209. 10 In conclusion, during the course of the week I learned two different ways to solve for inequalities. I found that by solving for W in the intervals 2 through 4 was a lot easier and quicker than completing all the steps in the first interval.

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